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1 vote
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Determine whether each of the following sequences are arithmetic, geometric or neither. If arithmetic, state the common difference. If geometric, state the common ratio.

-4, 12, -36, 108, -324, …
My answer below?
12, - 4 = 8
4 -12= -8 (neither)

User Loislo
by
2.0k points

2 Answers

20 votes
20 votes

Answer:

okay

Explanation:


for arithmetic \: progression \: there \: must \: be \: a \: common \: difference \\ \\ to \: get \: common \: difference \: {d} \: \\ get \: the \: the \: term \: infront \: minus \: the \: term \: before \\ say \: d = 12 - ( - 4) = 16 \\ d = - 36 - 12 = - 48 \\ d = 108 - ( - 36) = 144 \\ since \: d \: isnt \: uniform \: this \: is \: not \: arithmetic \: progression \\ \\ for \: geometric \: progression \: there \: must \: be \: a \: common \: ratio \: {r} \\ r \: is \: got \: by \: dividing \: the \: term \: infront \: by \: the \: term \: behind \\ \\ say \: r = 12 / ( - 4) = - 3 \\ r = ( - 36) / 12 = - 3 \\ r = 108 / ( - 36) = - 3 \\ since \: r \: is \: the \: same \: this \: is \: a \: geometric \: serie

User MastDrinkNimbuPani
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2.7k points
18 votes
18 votes


\qquad\qquad\huge\underline{{\sf Answer}}


\textbf{Let's see if the sequence is Arithmetic or Geometric :}


\textsf{If the ratio between successive terms is }
\textsf{equal then, the terms are in GP}


  • \sf{ (12)/(-4) = -3}


  • \sf{ (-36)/(12) = -3}


\textsf{Since the common ratio is same, }
\textsf{we can infer that it's a geometric progression}
\textsf{with common ratio of -3}

User Nandakishore
by
2.5k points
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