Answer:
A 98% confidence interval for the mean age is:
= ( 13.78, 19.10) months
Explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 16.44 months
Standard deviation r = 9.47 months
Number of samples n = 69
Confidence interval = 98%
z(at 98% confidence) = 2.33
Substituting the values we have;
16.44+/-2.33(9.47/√69)
16.44+/-2.33(1.140054028722)
16.44+/-2.656325886922
16.44+/-2.66
= ( 13.78, 19.10) months
Therefore, A 98% confidence interval for the mean age is:
= ( 13.78, 19.10) months