Answer:
a) test statistic,
![t_(s) = -4.20](https://img.qammunity.org/2021/formulas/mathematics/college/3qvznr98zk4ramsvdtwiwnwur91si7uhba.png)
b) P-value = 0.0001
c) It can be concluded from the hypothesis that the company's stock has a mean value that is not 7.52 million shares i.e. the mean stock has changed in recent years
Explanation:
There are 40 trading days, therefore, sample size, n = 40
Calculate the Sample mean:
![\bar x = (\sum x)/(n) \\\bar x = (4.153 +4.6228 + ...+...+5.4563)/(40)\\\bar x = 5.5945](https://img.qammunity.org/2021/formulas/mathematics/college/qfxg2bm9wk6p6f9incujn1jlfcsg8ahz3x.png)
Get the null and alternative hypothesis:
Null hypothesis,
![H_(0) : \mu = 7.52](https://img.qammunity.org/2021/formulas/mathematics/college/lvcpijpfbgxkf84z3mwsh1ofzfz3cbxovv.png)
Alternative hypothesis,
![H_(a) : \mu \\eq 7.52](https://img.qammunity.org/2021/formulas/mathematics/college/leafkc0agwcn6qb0rpkccxuuzpdmhkft5y.png)
Calculate the sample standard deviation:
![SD = \sqrt{(\sum (x - \bar x)^(2) )/(n - 1) } \\SD = \sqrt{((4.1531-5.5945)^(2) + (4.6228-5.5945)^(2)+...+ (5.4563-5.5945)^(2))/(39) } \\SD = \sqrt{(327.6161)/(39) } \\SD = 2.8983](https://img.qammunity.org/2021/formulas/mathematics/college/s65ljmhx3bujre0q3rnw7edxt646ho407a.png)
a) Calculate the test statistic:
![t_(s) = \frac{\bar{x} - \mu}{SD/√(n) } \\t_(s) = (5.5945 -7.52)/(2.8983/√(40) )\\t_(s) = -4.20](https://img.qammunity.org/2021/formulas/mathematics/college/okn258jla46jacirioqzpiqv9nsznrvr0w.png)
b) Calculate the P-value
Getting the P-value using the excel function:
P-value = (=T.DIST.2T(|ts|, df))
P-value = (=T.DIST.2T(4.20, 39))
P-value = 0.0001
c) If the level of significance,
![\alpha = 0.05](https://img.qammunity.org/2021/formulas/mathematics/college/445n2djo6b5zbv5df68kz5tjhh2puf9bol.png)
The P-value (0.0001) < α(0.05), the null hypothesis is rejected.
It can therefore be concluded from the hypothesis that the company's stock has a mean value that is not 7.52 million shares i.e. the mean stock has changed in recent years