Question

2. Um avião levanta voo de um solo segundo ângulo igual a 30º. Com uma velocidade de 100m/s em 1 minuto a altura máxima atingida pelo avião foi igual a:

Answer 1

height = 3000m

Explanation:

In order to calculate the height reached by the airplane, you first calculate the distance traveled by the airplane in one minute. The distance is given by:

`d=vt` (1)

v: speed of the airplane = 100m/s

t: time = 1 min = 60 s

you replace in the equation (1):

`d=(100m/s)(60s)=6000m`

The distance traveled by the airplane while it is going up, can be considered as a hypotenuse of a rectangle triangle.

The angle at which the airplane started to fly was 30°. Then, you can use the following trigonometric relation to calculate the height:

`sin(30\°)=(height)/(d)\\\\height=dsin(30\°)=(6000m)sin(30\°)=3000m`

hence, the height reached by the ariplane is 3000m