Given cos = 7/25, where is an angle in standard position terminating in quadrant IV, what is the value of tan ?

Question

asked Oct 9, 2021 196k views

1 Answer

Eliezer · Answer 1 · 2021-10-14T18:16:27+0000

Answer:

tanΘ = -
(24)/(7)

Explanation:

Given

cosΘ =
(7)/(25) =
(adjacent)/(hypotenuse)

The right triangle has sides 7, 24, 25 ← Pythagorean triplet

with adjacent = 7 and opposite = 24

Since position is in fourth quadrant then tanΘ < 0 , thus

tanΘ = -
(24)/(7)