Question

(WILL GIVE BRIANLIEST)

Please Help!

Question:
What is the solution set for the equation below?

(Look a the image, and the multiple choices are there)

Answer 1

option (c)
`\{-1,(4)/(3)\}` is the correct answer.

Explanation:

The given Quadratic equation is:

`3x^(2) -x-4=0`

Let us try to make factors:

`3x^(2) -x-4=0`

Here,
`-x` can be written as
`-4x + 3x` (Look at the coefficient of
`x^(2)` and constant part i.e. 3 and 4). So, the quadratic equation becomes:

`\Rightarrow 3x^(2) -4x+3x-4=0\\\text{Taking x common from }3x^(2) -4x \text{ and 1 common from }3x+4:\\\Rightarrow x(3x-4)+1(3x-4)=0\\\Rightarrow (x+1)(3x-4)=0\\\Rightarrow (x+1) =0\ or\ (3x-4) = 0\\\Rightarrow x =-1\ or\ x = (4)/(3)`

So, solution set for the equation
`3x^(2) -x-4=0` is:

`\{-1,(4)/(3)\}`

Hence, option (c)
`\{-1,(4)/(3)\}` is the correct answer.