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At our distance from the Sun, the intensity of solar radiation is 1370 W/m^2. The temperature of the Earth is affected by the greenhouse effect of the atmosphere. This phenomenon describes the effect of absorption of infrared light emitted by the surface so as to make the surface temperature of the Earth higher than if it were airless. For comparison, consider a spherical object of radius r with no atmosphere at the same distance from the Sun as the Earth. Assume its emissivity is the same for all kinds of electromagnetic radiation and its temperature is uniform over its surface.

Compute its steady-state temperature. Is it chilly?

User Tomsgu
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1 Answer

6 votes

Answer:

The steady-state temperature is
T = 4.85 ^oC

Yes it is chilly

Step-by-step explanation:

From the question we are told

The intensity of solar radiation is
I = 1320 \ (W)/(m^2)

Generally the Stefan Boltzmann Law is mathematically represented as


P = A \epsilon \sigma T^4

Where


P is the total power radiated


A is the surface area of the object


\epsilon is the emissivity

T is the temperature of the object


\sigma is the Boltzmann constant with a value
\sigma = 5.670 *10^(-8) (W)/(m^2 K^4)

Generally at steady state the input power to the object is equal to the output power from the object

i.e
P_A = P_B

Now
P_A

which is the input power to the object is not dependent on the object temperature and on the Boltzmann constant

thus
P_A is mathematically represented as


P_A = \epsilon IA_a

Where
A_a is absorptive surface area mathematically represented as


A_a = \pi r^2

Thus


P_A = \epsilon I \pi r^2

And
P_B which is the output power to the object is mathematically represented a


P_B = A_s \epsilon \sigma T^4

Where
A_s is the radiative surface area which is mathematically as


A_s = 4\pi r^2

So


P_B = 4\pi r^2 \epsilon \sigma T^4

=>
\epsilon I \pi r^2 = 4\pi r^2 \epsilon \sigma T^4

=>
T = \sqrt[4]{(I)/(4 \sigma ) }

substituting values


T = \sqrt[4]{(1370)/(4 * 5.670 *10^(-8) ) }


T = 278 \ K

Converting to degrees


T = 278 - 273


T = 4.85 ^oC

This implies that at steady state it is chilly

User Mark Nashat
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