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What must be the initial velocity of a rocket that accelerates for 10.2 seconds at 5.31 m/s2 and covers 3912 m?

A. 276 m
B. 356 m/s
C. 107 m/s
D. 384 m/s

1 Answer

2 votes

Answer: B

Explanation: 3912=10.2v +1/2(5.31)(10.2)^2 -> v≈ 356.45 (B)

User Tinkertime
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