Question

What is the mass of 1.450 mol Cd3N2?
124,2 g
234.7 g
529.6 g
738.9 g

Answer 1

529.6 g

Step-by-step explanation:

i took the test

Answer 2

529.6 g Cd₃N₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

1.450 mol Cd₃N₂

Step 2: Identify Conversions

Molar Mass of Cd - 112.41 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of Cd₃N₂ - 3(112.41) + 2(14.01) = 365.25 g/mol

Step 3: Convert

`\displaystyle 1.450 \ mol \ Cd_3N_2((365.25 \ g \ Cd_3N_2)/(1 \ mol \ Cd_3N_2) ) = 529.613 \ g \ Cd_3N_2`

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

529.613 g Cd₃N₂ ≈ 529.6 g Cd₃N₂