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Prove the identity (n-5)^2 - (6n-35)=(n-10)(n-6)

User Jono
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Answer:

(n-5)^2 - (6n-35)=(n-10)(n-6)

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  • n²-10n+25-6n+35 =
  • n²-16+60 = n²- 10n - 6n + 60 =
  • n(n-10) - 6(n-10) =
  • (n-10)(n-6)
User Adil Malik
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