Question

HELP SOLVE THANK YOU!

Answer 1

Solution 1: 1+1
`√(3)`

Solution 2: 1-
`1√(3)`

Explanation:

x^2-2=2x

x^2-2x-2=0

Use quadratic equation.

(-b+-
`√(b^2-4ac)`)/2a

(2+-
`√((-2)^2-4*1*-2)`)/2

(2+-
`√((4+8))`)/2

(2+-
`√(12)`)/2

Solution 1: (2+2
`√(3)`)/2=1+1
`√(3)`

Solution 2: 1-
`1√(3)`

Answer 2

Let's first move everything, the constants and variables to one side

`x^2-2=2x` ⇒
`x^2-2x-2=0`

The second form is in the general form of the quadratic equation:

⇒
`ax^2+bx+c = 0`

• a ⇒ 1
• b ⇒ -2
• c ⇒ -2

To find the value of x, we can use the quadratic formula:

⇒ look at the diagram attached

`x = (-b-√(b^2-4ac) )/(2a) =(2-√((-2)^2-4(1)(-2)) )/(2*1) =(2-√(4+8) )/(2) =(2-√(12) )/(2) =(2-2√(3))/(2) =1-√(3)`

`x = (-b+√(b^2-4ac) )/(2a) =(2+√((-2)^2-4(1)(-2)) )/(2*1) =(2+√(4+8) )/(2) =(2+√(12) )/(2) =(2+2√(3))/(2) =1+√(3)`

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Answer

To answer the question, just answer in the order I solved it, because the question asks you to put the answer in ascending order which means from least to greatest.

Hope that helps!