Question

Solve the equation using the quadratic formula. 3x^2-18=-6 a) x = ± 6 b)x = ± 2 c)x = 6 d)x = 2

Answer 1

Answer: B x=+-2

Explanation:

The Quadratic formula is -b+-
`-b+-\sqrt{(b^(2) -4ac)} /2a`

First make everything equal to 0

`3x^2-18+6=0`

Then Simplify

`3x^2-12=0`

Now use the formula where a=3, b=0, and c=-12

`0+-\sqrt{0^2-4(3)(-12)` divided by 2(3)

`0+-√(0-(-144))/6`

`(0+-12)/(6)`

then we get 12/6 and -12/6 which simplified is +-2