Answer:
Option (4).
Explanation:
Outer diameter of the hollow metallic ball = 10 centimeters
Outer radius of this ball =
= 5 cm
Volume of the outer ball
=
![(4)/(3)\pi (r)^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/mdjn2sbd8zc7d122zzj0rl3uwikoymei4j.png)
=
![(4)/(3)\pi (5)^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/1nhdtrt287z4twtutl2omw8lwgsy9m42fs.png)
Inner radius of the hollow metallic ball = (5 - 1) = 4 cm
Volume of the inner hollow ball
=
![(4)/(3)\pi (4)^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/quk38m75k00p2t0yyjlbq5rgrd6ns6q2y6.png)
Volume of the metal used in the metallic ball =
![V_(1)-V_(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dg5udwces4mwtaaki4ldfxhyqcfnfoy9fd.png)
=
![(4)/(3)\pi (5)^3-(4)/(3)\pi (4)^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8pclu1q9ip1bhvx9zwulhp1jet5js8njhr.png)
=
![(4)/(3)\pi [(5)^3-(4)^3]](https://img.qammunity.org/2021/formulas/mathematics/high-school/ejvyv2urt82jda4lq2p73rs94srjmusq8y.png)
Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.