Question

Which choice shows a function with a domain of {–4, –2, 2, 4}? On a coordinate plane, a vertical line is at x = 2. On a coordinate plane, a line goes through (negative 2, negative 2) and (0, negative 3). {(–4, 2), ( –2, 1), (2, 0), (4, 5)} {(1, –4), (0, –2), (2, 2), (6, 4)}

Answer 1

its c

Explanation:

Answer 2

`\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}`

Explanation:

Given: Domain of function is
`\left \{ -4,-2,2,4 \right \}`

To find: the function that has domain
`\left \{ -4,-2,2,4 \right \}`

Solution:

A function is a relation in which every element of the domain has a unique image in the co-domain.

For x = 2, domain is
`\left \{2 \right \}\\eq \left \{ -4,-2,2,4 \right \}`

For a line that passes through
`(-2,-2)\,,\,(0,-3)`,

domain must have 0 but
`0\\otin \left \{ -4,-2,2,4 \right \}`

Domain of
`\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}` is
`\left \{ -4,-2,2,4 \right \}`

Domain of
`\left \{ (1, -4), (0, -2), (2, 2), (6, 4) \right \}` is
`\left \{ 1,0,2,6 \right \} \\eq \left \{ -4,-2,2,4 \right \}`

So, answer is
`\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}`