Question

What is the equation of the line that is parallel to the given line and passes through the point -3, 2

3x-4y=-17
3x-4y=-20
4x+3y=-2
4x+3y=-6

Answer 1

Answer: It's D, which is 4x + 3y= -6.

Step-By-Step Explanation: The given line has a negative slope. so you know that the coefficients need matching signs, eliminating A and B. Plug in your given point and you get the constant 4(-3) +3(2) = -12+6 = -6.

Therefore you get D, which is 4x +3y = -6.

Answer 2

4x +3y = -6

Explanation:

The given line has negative slope, so the x- and y-coefficients in the standard-form equation must both have the same sign. The answer choices matching that requirement both have ...

4x +3y = constant

Put the given point in this expression to see the appropriate constant:

4(-3) +3(2) = -12 +6 = -6

The desired equation is ...

4x +3y = -6