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Let S = {1, 2, 3, ..., 12}. How many subsets of S, excluding the empty set, have an even sum but not an even product?

User Prashan
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6 votes

Answer:


2^(11)-1

Explanation:

The set S = {1, ,2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}. The total number of elements in the set (n) is 12. The sum of the elements in the set S is even if the sum of the elements of the complement of the set S is odd.

The number of pairs that can give an even sum is therefore
2^(n-1)=2^(12-1)=2^(11)

Since the empty set is excluded, The number of pairs that can give an even sum is therefore
= 2^(11)-1

User Abhay Agarwal
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