Question

Determine the number of zeros of the polynomial function.h(t) = (t − 6)2 − (t + 6)2

Answer 1

Explanation:

(t - 6)^2 = t^2 - 12t + 36

(t + 6)^2 = t^2 + 12t +36

(t - 6)^2 - (t + 6) = t^2 - 12t + 36 - (t^2 + 12t + 36)

(t - 6)^2 - (t + 6) = t^2 - 12t + 36 - t^2 - 12t - 36

(t - 6)^2 - (t + 6) = -24t The other 4 terms cancel out.

-24t = 0 Divide by - 24

t = 0

There is one root.