Question

How do you find the total sum of squared values?


`\sum (12)/(n = 3){r}^(2)`
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Answer 1

Explanation:

`\sum^(12)_(r=1) r^2 = (12(12+1)(2*12+1))/(6)= A`

`\sum_(r=3)^(12)= \sum_(r=1)^(12) - (r_1+r_2)`

`r_1= 1^2`

`r_2= 2^2`

you do your math!!