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How do you find the total sum of squared values?


\sum (12)/(n = 3){r}^(2)


User Androyal
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1 Answer

6 votes

Answer:

Explanation:


\sum^(12)_(r=1) r^2 = (12(12+1)(2*12+1))/(6)= A


\sum_(r=3)^(12)= \sum_(r=1)^(12) - (r_1+r_2)


r_1= 1^2


r_2= 2^2

you do your math!!

User Rama Bramantara
by
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