Answer:
It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.
Step-by-step explanation:
![d=v_ot+(1)/(2)at^2](https://img.qammunity.org/2021/formulas/physics/high-school/rnvc70qidyslok8egdd7hktyxjlkguj852.png)
Since the initial velocity of a dropped object is 0, we can make this the equation:
![d=(1)/(2)at^2 \\\\4410=\dfac{1}{2}(9.8)t^2 \\\\t^2=900](https://img.qammunity.org/2021/formulas/physics/high-school/jlqpsvw5zlrjlvju5nzjp5u8l7hoclfgp1.png)
![t=30\text{ seconds}](https://img.qammunity.org/2021/formulas/physics/high-school/na4811xk7f3vvc9ce7e2p2uqdp08cgq4f7.png)
The final velocity can be calculated with the formula:
![v_f=v_o+at](https://img.qammunity.org/2021/formulas/mathematics/high-school/ql6w0tzf4hn60us2kskv8k31rpq37pvnbw.png)
Once again, since there is no initial velocity:
![v_f=at \\\\v_f=(9.8)(30)=294m/s](https://img.qammunity.org/2021/formulas/physics/high-school/1fv33ewh1q4xpj5ji6vf62ifu1fl7vxhhh.png)
Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.
Hope this helps!