Answer:
![\boxed{r = 7.5\ cm}](https://img.qammunity.org/2021/formulas/mathematics/high-school/g1nhljyj0pgve9hr1f6rjg6lfx0j6umgws.png)
Explanation:
If M is the midpoint so AM = BM = AB/2 = 12 / 2 = 6 cm
Let's Consider a ΔOMB which would be a right angled triangle. So, We can use Pythagorean theorem to find the radius of the circle:
![c^2 = a^2+b^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z00tvngrpxzlbr37zqxzh75dqb06820msx.png)
Where c is hypotenuse (radius) , a is base ( MB = 6 cm ) , b is the perpendicular (OM = 4.5 cm)
![r^2 = 6^2+4.5^2\\r^2 = 36+20.25\\r^2 = 56.25](https://img.qammunity.org/2021/formulas/mathematics/high-school/fu0ak80zn75wnivek39b2gsk7dzxix55dc.png)
Taking sqrt on both sides
r ≈ 7.5 cm