45.3k views
4 votes
Find the length of radius.

Find the length of radius.-example-1
User Aries
by
6.1k points

2 Answers

3 votes

Answer:

radius = 7.5 cm

Explanation:

OM is the perpendicular bisector of AB, thus

∠ OMB = 90° and MB = 6 cm with OB being the radius of the circle

Using Pythagoras' identity in right triangle OMB

OB² = MB² + OM² = 6² + 4.5² = 36 + 20.25 = 56.25 ( square root both sides )

OB =
√(56.25) = 7.5

The radius = OB = 7.5 cm

User Manuelarte
by
5.3k points
3 votes

Answer:


\boxed{r = 7.5\ cm}

Explanation:

If M is the midpoint so AM = BM = AB/2 = 12 / 2 = 6 cm

Let's Consider a ΔOMB which would be a right angled triangle. So, We can use Pythagorean theorem to find the radius of the circle:


c^2 = a^2+b^2

Where c is hypotenuse (radius) , a is base ( MB = 6 cm ) , b is the perpendicular (OM = 4.5 cm)


r^2 = 6^2+4.5^2\\r^2 = 36+20.25\\r^2 = 56.25

Taking sqrt on both sides

r ≈ 7.5 cm

User The Bomb Squad
by
4.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.