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3 votes
The area of this trapezium

is
42.7cm^2

What
is
the height of the
of the shape ?​

User Preacher
by
4.5k points

1 Answer

4 votes

Answer:

The height of trapezium is 6.01cm

Explanation:

Given that the formula of area of trapezium is A = 1/2×(a+b)×h where a and b represents the length and h is the height. Next, you have to substitute the following values into the formula :


area = (1)/(2) * (a + b) * h


let \: area = 42.7 \\ let \: a = 9.2 \\ let \: b = 5


42.7 = (1)/(2) * (9.2 + 5) * h


42.7 = (1)/(2) * 14.2 * h


42.7 = 7.1 * h


h = 42.7 / 7.1


h = 6.01cm \: (3s.f)

Test :

Let a = 9.2,

Let b = 5,

Let h = 6.01,


area = (1)/(2) * (9.1 + 5) * 6.01


area = (1)/(2) * 85.342


area = 42.7 {cm}^(2) \: (proven)

User Nithin Jose
by
4.9k points