Question

Answr this fast u8fihikdxjko

Answer 1

(c) n(n+1)/√2

Explanation:

√2+√8+√18+√32+...

1√2+2√2+3√2+4√2+...+n√2

• First term= √2
• Common difference= √2
• Sₙ= n/2(2√2+(n-1)√2)= n/2(n√2+√2)=n(n+1)√2/2= n(n+1)/√2

Option (c) is correct