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\int\limits^8_2 {(√(x^2+64) )/(2x^2) } \, dxDon't get how to do this problem. Plz help!

User Logicalicy
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Answer:

Explanation:


\int\limits^8_2 {(1)/(√(x^2+64) ) } \, dx


u= x/8 \rightarrow dx = 8 du


x^2 = 64 u\rightarrow x^2+64 = 64 u^2 + 64 = 64 ( u^2 +1)


\int\limits^1_(1/4) {(1)/(8√(u^2+1) ) } \, 8du


\int\limits^1_(1/4) {(1)/(√(u^2+1) ) \, du


=ln(√(u^2+1)+u|_(1/4) ^1

User Maxime Esprit
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