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Find the missing lenghts of the sides

Find the missing lenghts of the sides-example-1
User Joel James
by
4.9k points

2 Answers

3 votes

Answer:

b = 8√3

c = 16

Explanation:

We cannot yet use the Pythagorean theorem because we only have one leg of the triangle

However, we can use trig identities to solve for the missing legs

I'll solve for b first so we can use the Pythagorean theorem after to find c

  • We can use any of the trig identities to solve for b, but I will use the tangent identity since it involves the leg we were given

  • tan(\alpha )=(opposite)/(adjacent)
  • Then solving for "opposite" which is our "b" will give us opposite = (adjacent)(tan(Ф))
  • Plugging in our known values we get b = (8)(tan(60°)) = (8)(√3) = 8√3

Now that we have two legs of the triangle we can use the Pythagorean theorem to solve for the remaining leg, c.

  • a² + b² = c² →
    c=√(a^2+b^2)
  • Plugging in our two legs of the triangle we get
    c=\sqrt{(8)^2+(8√(3) )^2}=√(64+192)=√(256)
  • c = 16
User Phoxd
by
5.4k points
5 votes

Answer:


b=8√(3), c=16

Explanation:

Since the ratios of sides in a 30-60-90 triangle are
1:√(3):2, b must be
8√(3) and c must be 16. Hope this helps!

User Bioffe
by
5.4k points