Question

A uniform shelf 1.8 meters long with mass 15 kg is mounted by a small hinge on a wall. The beam is held in a horizontal position by a cable that makes an angle of 37°. There is a 4.9-kg round light hanging down and is 0.55 meters from the wall. What is the tension in the supporting cable?

Answer 1

T = 153.72 N

Step-by-step explanation:

For this exercise we must use the conditions of translational and rotational equilibrium.

Let's set a frame of reference on the hinge, start by writing the rotational equilibrium relationship, suppose counterclockwise rotation is positive

We look for the components of the cable tension with trigonometry

cos 37 = Tₓ / T

sin 37 =
`T_(y)` / T

Tₓ = T cos 37

T_{y} = T sin 37

the expression for rotational equilibrium is

T_{y} L + Tₓ 0 - W L / 2 - W_light 0.55 = 0

where L is the length L= 1.8 m,

T_{y} = (W L/2 + W_lght 0.55) / L

T sin 37 = Mg /2 + m_light g 0.55 / L

T = (M / 2 + m_light 0.55 / L) g / sin 35

let's calculate

T = (15/2 + 4.9 0.55 / 1.8) 9.8 / sin 35

T = 153.72 N