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PLZ HELP QUICKLY!!!!!!!

Fill in the blank with a constant, so that the resulting quadratic is the square of a binomial.


x^2+(4)/(5)x + \underline{~~~~}

User Tom Walker
by
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2 Answers

3 votes

Answer:


$x^2+(4)/(5)x+(4)/(25) $


$\left(x+(2)/(5) \right)^2$

Explanation:

Taking the middle coefficient:


ax^2+bx+c


$c=\left((b)/(2) \right)^2$


$c=\left(((4)/(5) )/(2) \right)^2$


$c=\left((4 )/(10) \right)^2$


$c=\left((2 )/(5) \right)^2$


$c=(4)/(25) $

Completing the square:


$x^2+(4)/(5)x+(4)/(25) $


$\left(x+(2)/(5) \right)^2$

User Kapex
by
3.4k points
2 votes
To complete the square (x+2/5)^2 it would be x^2+(4/5)x+4/25
User Dheeraj Reddy
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3.5k points