Question

Recall specific heat of water is 4186 j/kg/C. Find the specific heat of sample.

Water. Sample
Mass 109 192
Internal temperature. 21. 67
Final temperature. 30.1. 30.1

Answer 1

To find the specific heat of the sample, use the formula Q=mcΔT, where Q is the heat energy, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature. Plug in the values for the water sample and calculate the result.

Step-by-step explanation:

The specific heat of water is 4.184 J/g °C, which means it requires 4.184 J to heat 1 gram of water by 1 °C. To find the specific heat of the sample, we can use the formula:

Q = mcΔT

Where Q is the heat energy, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values for the water sample:

Q = (192 g) * (4.184 J/g °C) * (30.1 °C - 67 °C)

Calculate the result to find the specific heat of the sample.

Answer 2

Shown by explanation;

Step-by-step explanation:

The heat of the sample = mass ×specific heat capacity of the sample × temperature change(∆T)

Assumption;I assume the mass of the samples are : 109g and 192g

∆T= 30.1-21=8.9°c.

The heat of the samples are for 109g are:

0.109 × 4186 × 8.9 =4060.84J

For 0.192g are;

∆T= 67-30.1-=36.9°c

0.192 × 4186×36.9=29656.97J