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What is the solution set for the inequalities x^3<0 or 4x^4>x^2?

1 Answer

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Answer:

(x < 0) ∪ (x > 1/2)

Explanation:

First inequality:

x^3 < 0

x < 0 . . . . . take the cube root

Second inequality:

4x^4 > x^2

4x^4 -x^2 > 0

x^2(4x^2 -1) > 0

Any non-zero x will make the first factor positive. The product will be positive only when the second factor is positive, for x^2 > 1/4

x^2 > 1/4

|x| > 1/2 . . . . . take the square root

x < -1/2 or x > 1/2

The first part of this solution is already covered by the solution to the first inequality. Hence the solution set for the system of inequalities is ...

(x < 0) ∪ (x > 1/2)

User Donald Miner
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