Question

Find the area of a triangle, two sides of which are 10 cm and 16 cm and the perimeter is 38 cm.

Answer 1

Explanation:

third side=38-(10+16)=38-26=12

sides are 10 cm, 12 cm , 16 cm.

2s=10+12+16=38

s=38/2=19

area=√(s(s-a)(s-b)(s-c))

=√[19(19-10)(19-12)(19-16)]

=√[19×9×7×3]

=3√391 cm²

≈59.32 cm²

Answer 2

perimeter of triangle=a+b+c

but first we have to find the value of the third side

so here,

a=10

b=16

c=x

now,

10+16+x=38

26+x=38

x=38-26

x=12

area of triangle= 1/2×base×height

= 1/2×16×9

(height = 9 ,but why??

here it is,

using Pythagoras theorem,

m²-1=8

m²+1=10

so,

m=9)

continuation:

=8×9

=72

the area is 72 cm

hope it helped :-)