Question

Balance the following chemical equations.

a) Ba Cl2 + H2SO4  BaSO4 + HCl.

b) Calcium hydroxide + Carbon dioxide  Calcium carbonate + Water.

c) Aluminum + Copper chloride  Copper + Aluminum chloride

d) Sulphur dioxide + Oxygen  Sulphur trioxide

e) NH3+ CuO  Cu + N2 + H2O​

Answer 1

See the explanation

Step-by-step explanation:

In this question we have to take into account that we have to get the same amount of atoms on both sides, so:

Reaction 1

`BaCl_2~+~H_2SO_4~=>~BaSO_4~+~2HCl`

We have 1 Ba, 2 Cl, 2 H and 4 O on both sides

Reaction 2

`Ca(OH)_2~+~CO_2~=>~CaCO_3~+~H_2O`

We have 1 Ca, 2O, 2 H and 1 C on both sides

Reaction 3

`2Al~+~3CuCl_2~=>~2 AlCl_3~+~3Cu`

We have 2 Al, 3 Cu, and 3 Cl on both sides

Reaction 4

`2SO_2~+~O_2~=>~2SO_3`

We have 2 A and 6O on both sides

Reaction 5

`2NH_3~+~3CuO~=>~3Cu~+~N_2~+~3H_2O`

We have 2 N, 3 H, 3 Cu and 3O on both sides.

I hope it helps