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Please i need the answers of question 1 and 2

Please i need the answers of question 1 and 2-example-1

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Answer:

1. Option D. 1.86x10^19 electrons.

2. Option B. 4.0x10^–16C.

Step-by-step explanation:

1. Determination of the number of electrons in – 3C.

This can be obtained as follow:

–1C = 6.2x10^18 electrons

Therefore, –3C = –3C/–1C x 6.2x10^18 electrons = 1.86x10^19 electrons.

Therefore, there are 1.86x10^19 electrons in –3C.

2. Determination of the number of coulomb in +2500e.

This can be obtained as follow:

1e = 1.602176x10^–19C

Therefore, 2500e =

2500 x 1.602176x10^–19 = 4.0x10^–16C

Therefore, 2500e contains 4.0x10^–16C

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