Answer:
Explanation:
Let x be the random variable representing the miles per gallon of Chevrolet Cobalt in highway driving. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
From the information given,
µ = 33
σ = 4
a) the probability that a randomly selected Cobalt gets more than 34 miles per gallon is expressed as
P(x > 34) = 1 - P(x ≤ 34)
For x = 34,
z = (34 - 33)/4 = 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.5987
P(x > 34) = 1 - 0.5987
P(x > 34) = 0.4013
b) since sample size is given, the formula would be
z = (x - µ)/(σ/n)
n = 16
z = (34 - 33)/(4/√16)= 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x > 34) = 1 - 0.8413
P(x > 34) = 0.1587
c) Since the population is normally distributed, then, the sample is also normally distributed. The correct option is
Yes, we could, because the distribution of the sample mean is always normal regardless of the sample size