Question

A man who has male pattern baldness (X^bY) marries a woman who does not carry the allele (X^BX^B). What genotypic ratios would be expected of their children?

Answer 1

2
`X^BX^b`:2
`X^BY`

Step-by-step explanation:

The genotypic ratio of expected of their offspring would be 2
`X^BX^b`:2
`X^BY`.

From the illustration, the genotype of the man with male pattern baldness is
`X^bY` while the genotype of the woman without the baldness allele is
`X^BX^B`.

Crossing the two genotypes in marriage:

`X^bY` x
`X^BX^B`

Progeny:
`X^BX^b`
`X^BX^b`
`X^BY`
`X^BY`

Hence, the genotypic ratio of the offspring becomes:

2
`X^BX^b`:2
`X^BY`