Question

What is the molality of a solution made by dissolving 0.0816 moles of

C6H1206 into 150.0 g of water?

Answer 1

m = 0.544 moles/kg

Step-by-step explanation:

To do this, we need to use the expression for molality of a solution which is:

m = n / kg water

Where:

n: moles of solute

m: molality of solution

In this case, we have the moles of the solute, which is the C6H12O6 and the grams of water, and these grams would have to be turn into kg. Let's do this first:

kg of water = 150 g * 1 kg / 1000 g = 0.150 kg of water.

Now, replacing in the above expression of molality, we can calculate the molality of the solution:

m = 0.0816 / 0.150

m = 0.544 moles/kg