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1 vote
What is the value of the arithmetic series below?

S19= 19/E/k=1 (4-3k)


a) -494

b) -104

c) -53

d) -52

User Vencaslac
by
5.4k points

2 Answers

4 votes

Answer:

the answer is A. -494

edge 2021

Explanation:

User Ggirtsou
by
5.3k points
2 votes

Answer:

(A)-494

Explanation:

Given the arithmetic series


S_(19)=\sum_(k=1)^(19)4-3k

The terms in the sequence are:

  • When k=1, 4-3k=4-3(1)=1
  • When k=2, 4-3k=4-3(2)=-2
  • When k=3, 4-3k=4-3(3)=-5

Therefore, the terms in the sequence are: 1, -2, -5, ...

First term, a =1

Common difference, d=-2-1=-3

The sum of an arithmetic series,
S_n=(n)/(2)[2a+(n-1)d]

Therefore:


S_(19)=(19)/(2)[2(1)+(19-1)(-3)]\\=9.5[2+18*-3]\\=9.5[2-54]\\=9.5*-52\\=-494

The correct option is A.

User FlavienBert
by
5.5k points