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Express f(x) = 3 cos x + 5 sin x as Rsin(x + o), where e
is an acute angle in radians.​

User Gevorg
by
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1 Answer

3 votes

Answer:

√34sin(x + 0.33π)

Explanation:

The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.

R = √a²+b²


e = tan^(-1)(b)/(a)

Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;

a = 3, b = 5

R = √3²+5²

R = √9+25

R =√34


e = tan^(-1) (5)/(3) \\e = 59.09^(0)

in radians;


e =(\pi )/(180)*59.09\\ e = 0.33\pi rad

3 cos x + 5 sin x = √34sin(x + 0.33π)

User Otmezger
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