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Prove that, in a right triangle with a 15° angle, the altitude to the hypotenuse is one fourth of the hypotenuse (without using trigonometric functions).

User AXMIM
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1 Answer

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Answer:

a = b/4

Explanation:

Let a be the altitude to the hypotenuse and b be the hypotenuse. The 15° angle faces a and the right angle faces b.

Using the sine rule,

a/sin15 = b/sin90

a = bsin15/sin90

= 0.25b

= 25b/100

= b/4

User Sergey Afinogenov
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