If 4520 kJ of heat is needed to boil a sample of water, what is the mass of the sample of water (ΔHvaporiztion = 2260kJ/kg)?

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asked Jul 22, 2021 11.9k views

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If 4520 kJ of heat is needed to boil a sample of water, what is the mass of the sample of water (ΔHvaporiztion = 2260kJ/kg)?

Chemistry
middle-school

Sigute asked

by Sigute

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Answer:2kg

Explanation:heat gained=heat lost

mass x 2260=4520

4530÷2260

And=2kg

Jonny Brooks answered Jul 28, 2021

by Jonny Brooks

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