Question

What is the equation for ⨀C?

Answer 1

Answer: Choice A. (x-2)^2 + (y+2)^2 = 16

Work Shown:

(h,k) = (2,-2) is the center. So h = 2 and k = -2

r = 4 is the radius. We go 4 units from the center C to point P

Therefore,

(x-h)^2 + (y-k)^2 = r^2

(x-2)^2 + (y-(-2))^2 = 4^2

(x-2)^2 + (y+2)^2 = 16

Answer 2

A

Explanation:

r^2 = (x - k)^2 + (y - h)^2