Question

Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight camping stoves. Suppose a lighter contains 7.96 mL of butane (d = 0.579 g/mL). (a) How many grams of oxygen are needed to burn the butane completely?

Answer 1

The correct answer will be "4.60 g".

Step-by-step explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒
`Mass \ of \ Butane = Density* Volume`

On putting the estimated values, we get

⇒
`=0.579* 7.96`

⇒
`=4.60 \ g`