Question

While a dog runs forward, its

owner pulls back with a 22.4 N force at a 115º direction, doing
-42.3 J of work. How far did the
dog move?​

Answer 1

4.47 M.

Step-by-step explanation:

I do Acellus and just got it correct!

Answer 2

d = 100.56 m

Step-by-step explanation:

It is given that,

Force acting on the dog is 22.4 N

Angle at which the force is applied is 115 º

Work done is - 42.3 J

We need to find the distance covered by the dog. The work done by an object is given by :

`W=Fd\cos\theta`

d = distance covered by the dog

`d=(W)/(\cos\theta)\\\\d=(-42.5)/(\cos(115))\\\\d=100.56\ m`

So, the dog moves a distance of 100.56 m.