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How's the economy? A pollster wants to construct a confidence interval for the proportion of adults who believe that economic conditions are getting better. Part: 0 / 20 of 2 Parts Complete Part 1 of 2 (a) A poll taken in July estimates this proportion to be . Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of ? A sample of adults is needed to obtain a confidence interval with a margin of error of .

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Complete Question

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Answer:

a

The sample size is
n =944

b

The sample size is
n_b = 1068

Explanation:

From the question we are told that

The proportion is mathematically represented as
\r p = 0.33

The marginal error is
e = 0.03

The confidence level is 95 % = 0.95

The z-value of the confidence level is


z_c = 1.96

This value is obtained from the z table

The sample size is mathematically evaluated as


n = [(z_c)/(e) ]^2 * \r p(1- \r p)

substituting values


n = [(1.96)/(0.03) ]^2 * 0.33 (1- 0.33)


n =944

If no estimate is available the let assume
\r p = 0.50

So


n_b = [(z_c)/(e) ]^2 * \r p(1- \r p)

substituting values


n_b = [(1.96)/(0.03) ]^2 * 0.50 (1- 0.50)


n_b = 1068

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