Question

An arrow is shot vertically upward at a rate of 160 feet per second from ground level. Use the projectile formula

h
=
−
16
t
2
+
v
0
t
+
h
0
to determine when the arrow hit the ground.

Answer 1

To determine when the arrow hits the ground, use the projectile formula h = -16t^2 + v0t + h0. In this case, the arrow is shot vertically upward at a rate of 160 feet per second from ground level. The arrow hits the ground after 10 seconds.

Step-by-step explanation:

To determine when the arrow hits the ground, we can use the projectile formula h = -16t^2 + v0t + h0. In this case, the arrow is shot vertically upward, so the initial vertical velocity v0 is 160 feet per second. The initial height h0 is the ground level, which is 0 feet. To find the time t when the arrow hits the ground, we need to set h = 0 and solve for t.

Using the formula -16t^2 + 160t = 0, we can factor out a common factor of t and solve for t:

t(-16t + 160) = 0

Setting each factor to 0, we have t = 0 and -16t + 160 = 0.

Since time cannot be negative, we discard the t = 0 solution. Solving -16t + 160 = 0, we find t = 10 seconds. Therefore, the arrow hits the ground after 10 seconds.

Answer 2

after 10 seconds

Step-by-step explanation:

h=-16t^2+v0*t+h0

ground level is h0 with a measure of 0

160 is v or velocity

0=-16t^(2)+160t+0

0=-16t^(2)+160t

0=16t(-t+10)

0/16t=(-t+10)

0=-t+10

-10=-t

10=t

t=10