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An eagle is flying horizontally at a speed of 1.90 m/s when the fish in her talons wiggles loose and falls into the lake 5.10 m below. Calculate the velocity (in m/s) of the fish relative to the water when it hits the water. (Assume that the eagle is flying in the +x-direction and that the +y-direction is up.)

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Answer:

The correct answer will be "16.74 m/s".

Step-by-step explanation:

The given values are:

Speed = 1.90 m/s

Height = 5.10 m

g = 9.8 m/s²

On applying energy conservation, we get


(1)/(2)mV_(1)^2+mgH=(1)/(2)mV_(2)^2

On putting the estimated values, we get


V_(2)=√(1.9^2+2* 9.8* 5.1)


=√(3.61+2* 9.8* 5.1)


=√(5.61* 9.8* 5.1)


=√(280.38)


=16.74 \ m/s

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