Question

Which two values of x satisfy the equation square root 3-2cos x = 2?

Answer 1

Answer: x=2π/3 and x=4π/3

Explanation:

The equation we have is
`√(3-2cosx) =2`. All we have to do is get cosine alone to find the 2 values of x.

`3-2cosx=4\\-2cosx=1\\cosx=-(1)/(2)`

Now that we have our cosine left, we can use our unit circle to figure out when does cosx=-1/2. Cosine is the x value of the coordinate.

x=2π/3

x=4π/3