Question

How do I solve this? (please help to find what goes in the boxes as well)

Answer 1

First Box: Factor by difference of squares

Second Box: It has all perfect squares

Third Box: see my work

Explanation:

We have the equation
`4x^2=36`

Before we do anything, let us bring all of the terms to the left side

`4x^2-36=0`

Now that we have moved the terms to one side, it is clear that we have a difference of squares.

-Work-

`4x^2=36\\\\4x^2-36=0\\\\(2x+6)(2x-6)=0\\\\`

-

`2x+6=0\\\\2x=-6\\\\x=-3`

-

`2x-6=0\\\\2x=6\\\\x=3`