Question

Maryann is tracking the change in her vertical jump over 6 months. Use the table to write a linear function that models her jump distance.

Month Vertical Jump in inches
0 16
2 17
4 18
6 19
f of x equals one half times x plus 16
f of x equals one half times x plus 19
f(x) = 2x + 16
f(x) = 2x + 19

Answer 1

A linear function that models her jump distance is
`f(x)=(1)/(2)x+16`

Explanation:

Month Vertical Jump in inches

0 16

2 17

4 18

6 19

We are supposed to find a linear function that models her jump distance.

Two point slope form :
`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

`(x_1,y_1)=(0,16)\\(x_2,y_2)=(2,17)`

Substitute the values in the formula :

`y-16=(17-16)/(2-0)(x-0)\\y-16=(1)/(2)x\\y=(1)/(2)x+16`

So,
`f(x)=(1)/(2)x+16`

So, Option A is true

Hence a linear function that models her jump distance is
`f(x)=(1)/(2)x+16`