Question

What is the vertical asymptote for the reciprocal of y=8x-4

Answer 1

The vertical asymptote for the reciprocal of the function y=8x-4 is at x=1/2.

Step-by-step explanation:

The vertical asymptote for the reciprocal of the function y=8x-4 can be found by setting the denominator to zero once we express the reciprocal function. The reciprocal function is y = 1/(8x-4). To find the vertical asymptote, we set the denominator equal to zero and solve for x.

So, we get 8x - 4 = 0. Solving for x, we add 4 to both sides getting 8x = 4, and then divide by 8 to isolate x, resulting in x = 1/2. Therefore, the vertical asymptote is at x = 1/2.

Answer 2

The vertical asymptote for the reciprocal of y=8x-4 is
`(1)/(2)`

Step-by-step explanation:

Given Equation :
`y = 8x-4`

Reciprocal of given equation =
`(1)/(y)=(1)/(8x-4)`

Now to find the vertical asymptote

`(1)/(y)=(1)/(8x-4)`

Equate denominator to 0

8x-4=0

8x=4

`x=(4)/(8)`

`x=(1)/(2)`

So, The vertical asymptote is
`(1)/(2)`

Hence the vertical asymptote for the reciprocal of y=8x-4 is
`(1)/(2)`