Question

Write the equilibrium constant expression for this reaction: CH3OH (aq)+Cl-(aq)-> CH3Cl(aq)+OH-(aq)

Answer 1

Answer:
`K_c=([CH_3Cl]* [OH^-])/([CH_3OH]* [Cl^-])`

Step-by-step explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.

The given balanced equilibrium reaction is:

`CH_3OH(aq)+Cl^-(aq)\rightleftharpoons CH_3Cl(aq)+OH^-(aq)`

The expression for equilibrium constant for this reaction will be,

`K_c=([CH_3Cl]* [OH^-])/([CH_3OH]* [Cl^-])`

Thus the equilibrium constant expression for this reaction is
`K_c=([CH_3Cl]* [OH^-])/([CH_3OH]* [Cl^-])`