61.4k views
5 votes
Suppose a person may use any six different letters except a, e, i, o, or u, to make a computer password. Using permutations, find the number of possible six-letter, lower-case passwords.

User Sjoerd
by
8.4k points

1 Answer

4 votes

Answer:

39,070,080 possible passwords

Explanation:

The complete alphabet has 26 letters. Removing the 5 vowels, we have 21 letters.

We want to make groups of 6 letters, and the order of each letter matters, because it will create a different password, so we can write a permutation to solve this problem.

The number of elements is 21, and the group has 6 elements, so we have a permutation of 21 choose 6:

P(21,6) = 21! / (21-6)! = 21! / 15! = 21 * 20 * 19 * 18 * 17 * 16 = 39,070,080 possible passwords

User Artem Baranovskii
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories